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Subject :
Calculus
Topic :
Integration
When integrating the following
true
false :
2x
3
-5x + C ]
4
2
> 100
true
false :
∫ -5 dx = 5x + C
true
false :
∫ (6x
2
- 5) dx = 2x
3
- 5x + C
true
false :
∫ (6x
2
- 5) dx since 5 is constant it can be ignored
Subject :
Calculus
Topic :
Integration
When integrating the following
true
false :
2x
3
-5x + C ]
4
2
> 100
true
false :
∫ -5 dx = 5x + C
true
false :
∫ (6x
2
- 5) dx = 2x
3
- 5x + C
true
false :
∫ (6x
2
- 5) dx since 5 is constant it can be ignored